How do you solve #(x+5)^2=9#?

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Answer 1 · 2016-07-28T10:17:34

#x=-2, x=-8#

#(x+5)^2=9#

Taking square Root,

#x+5=sqrt9=+-3#

# x+5=+3 rArr x=3-5=-2#, or,

# x+5=-3 rArr x=-3-5=-8#

These roots satisfy the given eqn.

Hence, #x=-2, x=-8# are the solns.