How do you solve $(x - 5) (x + 6) = 12$ $(x-5)(x+6)=12$ ?

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Answer 1 · 2018-04-28T08:42:20

$x = 6 or - 7$ $x=6 or -7$

$(x - 5) (x + 6) = 12$ $(x-5)(x+6)=12$

Expand,

$x^{2} + x - 30 = 12$ $x^2+x-30=12$

Subtract $12$ $12$ from both sides,

$x^{2} + x - 42 = 0$ $x^2+x-42=0$

Factor,

$(x - 6) (x + 7) = 0$ $(x-6)(x+7)=0$

Solve,

$x = 6 or - 7$ $x=6 or -7$

How do you solve (x−5)(x+6)=12(x-5)(x+6)=12?