How do you solve $( x - 6)^2 = 19$ ?

Question

2163 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-14T04:49:23

$x=6+sqrt19, 6-sqrt 19$

$(x-6)^2=19$

Take the square root of both sides.

$x-6=+-sqrt 19$

Add $6$ to both sides of the equation.

$x=6+-sqrt 19$

Solve for $x$ .

$x=6+sqrt19, 6-sqrt 19$

How do you solve ( x - 6)^2 = 19( x - 6)^2 = 19?