How do you solve ${(x - 6)}^{2} = 49$ $(x - 6)^2= 49$ ?

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Answer 1 · 2016-05-09T00:24:22

$x = - 1, 13$ $x = -1, 13$

$(x - 6) = \sqrt{49}$ $(x - 6) = sqrt(49)$

$x - 6 = \pm 7$ $x - 6 =+- 7$

$x = - 7 + 6 or 7 + 6$ $x = -7 + 6 or 7 + 6$

$x = - 1 or 13$ $x = -1 or 13$

Hopefully this helps!

How do you solve (x−6)2=49(x - 6)^2= 49?