How do you solve $( x + 7)^2 = -11$ ?

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Answer 1 · 2017-03-22T16:14:58

$x = -7+isqrt 11 and -7-isqrt 11$

$(x + 7)^2 = -11$

$(x + 7) = +-sqrt(-11)$

$(x + 7) =+- sqrt(-1 * 11)$

$(x + 7) = +-sqrt (-1) * sqrt 11$

$(x + 7) = +- i * sqrt 11$ , where $i^2 = -1$

$x = -7+-isqrt 11$

$x = -7+isqrt 11 and -7-isqrt 11$

How do you solve ( x + 7)^2 = -11( x + 7)^2 = -11?