How do you solve ${(x - 7)}^{2} = 9$ $(x-7)^2=9$ ?

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How do you solve ${(x - 7)}^{2} = 9$ $(x-7)^2=9$ ?

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Answer 1 · 2016-04-07T10:03:40

$x = 10, 4$ $x = 10, 4$

Explanation:

${(x - 7)}^{2} = 9$ $(x - 7)^2 = 9$

Square root both sides to get rid of the ${()}^{2}$ $()^2$ . This gives two answers: $3$ $3$ and $- 3$ $-3$ . Begin by solving with the answer $3$ $3$ .

$x - 7 = 3$ $x - 7 = 3$

Add $7$ $7$ to get rid of the $- 7$ $-7$

$x = 10$ $x = 10$

Now for $- 3$ $-3$ ,

$x - 7 = - 3$ $x - 7 = -3$
$x = 4$ $x = 4$

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How do you solve ${(x - 7)}^{2} = 9$ $(x-7)^2=9$ ?

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How do you solve (x-7)^2=9(x−7)2=9 (x-7)^2=9?

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How do you solve ${(x - 7)}^{2} = 9$ $(x-7)^2=9$ ?