How do you solve $x²-7x+4=0$ using the quadratic formula?

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Answer 1 · 2016-05-10T21:41:57

$x = 7/2+-sqrt(33)/2$

$x^2-7x+4=0$ is in the form $ax^2+bx+c=0$ with $a=1$ , $b=-7$ and $c=4$ .

This has roots given by the quadratic formula:

$x = (-b+-sqrt(b^2-4ac))/(2a)$

$=(7+-sqrt((-7)^2-(4*1*4)))/(2*1)$

$=(7+-sqrt(49-16))/2$

$=(7+-sqrt(33))/2$

$=7/2+-sqrt(33)/2$

How do you solve x²-7x+4=0x²-7x+4=0 using the quadratic formula?