How do you solve $(x - 9)^2 = 1$ ?

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Answer 1 · 2016-07-30T18:59:15

If a number to the square is $1$ , that number is either $1$ or $-1$

Thus if $(x-9)^2=1$ we know that either $(x-9)=1$ or $(x-9)=-1$ .

Hence we have either $x=10$ or $x=8$

How do you solve (x - 9)^2 = 1(x - 9)^2 = 1?