Question

How do you solve `x-\frac{15}{x}=2`?

Answer 1

`x=-3" or "x=5`

Explanation:

`"multiply all terms by "x`

`x^2-15=2x`

`x^2-2x-15=0larrcolor(blue)"in standard form"`

`"the factors of - 15 which sum to - 2 are - 5 and + 3"`

`(x-5)(x+3)=0`

`"equate each factor to zero and solve for x"`

`x+3=0rArrx=-3`

`x-5=0rArrx=5`