Question

How do you solve `x(x-7) = 12`?

Answer 1

Given `x(x-7) = 12`
we can convert the given form into a standard parabolic quadratic and solve using one of several techniques to obtain the solution(s).

`x(x-7) = 12`

`x^2-7x -12 = 0`

For a quadratic in the form
`ax^2+bx+c=0`
we can use the quadratic formula for roots
`x = (-b+-sqrt(b^2-4ac))/(2a)`

In this case
`x = (7+-sqrt(49+48))/2`

`x=( 7+-sqrt(97))/2`