How do you solve $x-y=6$ and $2x + 3y =2$ using matrices?

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Answer 1 · 2017-09-28T16:24:58

The solution is $((x),(y))=((4),(-2))$

Let's perfom the Gauss-Jordan elimination on the augmented matrix

The augmented matrix is

$((1,-1,|,6),(2,3,|,2))$

Let`s perform the row operations

$R2larr(R2-2R1)$

$((1,-1,|,6),(0,5,|,-10))$

$R2larr(R2)/(5)$

$((1,-1,|,6),(0,1,|,-2))$

$R1larr(R1+R2)$

$((1,0,|,4),(0,1,|,-2))$

The solution is $((x),(y))=((4),(-2))$

Answer 2 · 2017-10-13T23:10:10

$x=4, y=-2$

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$x=4, y=-2$

How do you solve x-y=6x-y=6 and 2x + 3y =22x + 3y =2 using matrices?