How do you solve y^2-12y=-35 by completing the square?

2 Answers
1s2s2p
May 9, 2018

(y-6)^2-1=0

Explanation:

y^2-12y+35-0

(y-6)^2+a=0

y^2-12y+36+a=y^2-12y+35

a=-1

(y-6)^2-1=0

Jim G.
May 9, 2018

y=5" or "y=7

Explanation:

"to solve using "color(blue)"completing the square"

" add "(1/2"coefficient of the y-term")^2" to both sides"

rArry^2+2(-6)ycolor(red)(+36)=-35color(red)(+36)

rArr(y-6)^2=1

color(blue)"take the square root of both sides"

sqrt((y-6)^2)=+-sqrt1larrcolor(blue)"note plus or minus"

rArry-6=+-1

"add 6 to both sides"

rArry=6+-1

rArry=6-1=5" or "y=6+1=7

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