How do you solve $y = 2 x^{2} + x - 3$ $y = 2x^2 + x - 3$ ?

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Answer 1 · 2015-10-11T22:27:06

Solve y = 2x^2 + x - 3 = 0

Ans: 1 and $- \frac{3}{2}$ $-3/2$

Since (a + b + c = 0), use the Shortcut. The 2 real roots are $x = 1$ $x = 1$ and $x = \frac{c}{a} = - \frac{3}{2} .$ $x = c/a = -3/2.$

How do you solve y = 2x^2 + x - 3y=2x2+x−3y = 2x^2 + x - 3?