How do you solve $y = 3x^2 − 2x − 5$ ?

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Answer 1 · 2017-09-07T17:30:26

$3x^2-2x-5=0$

$3x^2+3x-5x-5=0$

$3x*(x+1)-5*(x+1)=0$

$(x+1)*(3x-5)=0$

Thus, $x1=-1$ and $x2=5/3$ .

I used distribution and collection rules of polynomials.

How do you solve y = 3x^2 − 2x − 5 y = 3x^2 − 2x − 5 ?