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How do you solve $Z = \frac{g - k}{a}$ $Z=(g-k)/a$ for g?

1 Answer

Vinícius Ferraz

Oct 23, 2016

$g = a Z + k$ $g = aZ + k$

Explanation:

somebody took g,
subtracted k
then divided by a.

now we need the inverse.
multiply by a,
sum k.

$a Z = g - k$ $aZ = g - k$

$a Z + k = g$ $aZ + k = g$

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