How do you subtract $(3x^3 – 4x^2 + 6x) – (5x^3 + 2x^2 – 3x)$ ?

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Answer 1 · 2018-04-13T09:44:54

$-2x^3-6x^2+9x$

$(3x^3–4x^2+6x)–(5x^3+2x^2–3x)$

$–(5x^3+2x^2–3x)$
$=–1xx(5x^3+2x^2–3x)$
$=(–1xx5x^3)+(–1xx2x^2)+(–1xx–3x)$
$=–5x^3-2x^2+3x$

$=3x^3–4x^2+6x" "color(blue)(–5x^3-2x^2+3x)$

$=3x^3color(blue)(–5x^3)–4x^2color(blue)(-2x^2)+6xcolor(blue)(+3x)$

$=color(red)(-2x^3-6x^2+9x)$

How do you subtract (3x^3 – 4x^2 + 6x) – (5x^3 + 2x^2 – 3x)(3x^3 – 4x^2 + 6x) – (5x^3 + 2x^2 – 3x)?