How do you subtract $(6 x^{2} + x + 4) - (x^{2} - x + 9)$ $(6x^2 + x + 4) - (x^2 - x + 9)$ ?

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Answer 1 · 2018-05-26T15:44:41

$5 x^{2} + 2 x - 5$ $5x^2 + 2x - 5$

$(6 x^{2} + x + 4) - (x^{2} - x + 9)$ $(6x^2 + x + 4) - (x^2 - x + 9)$

means:

$(6 x^{2} + x + 4) - 1 (x^{2} - x + 9)$ $(6x^2 + x + 4) -1 (x^2 - x + 9)$

use the distributive property:

$6 x^{2} + x + 4 - x^{2} + x - 9$ $6x^2 + x + 4 - x^2 + x - 9$

combine like terms:

$5 x^{2} + 2 x - 5$ $5x^2 + 2x - 5$

How do you subtract (6x2+x+4)−(x2−x+9)(6x^2 + x + 4) - (x^2 - x + 9)?