How do you subtract $(8 x^{2} + 5) - (3 x^{2} - x + 7)$ $(8x^2 + 5) − (3x^2 − x + 7)$ ?

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Answer 1 · 2018-04-05T13:45:38

$5 x^{2} + x - 2$ $5x^2+x-2$

Distribute the negative sign through the second term, yielding

$8 x^{2} + 5 - 3 x^{2} - (- x) - 7$ $8x^2+5-3x^2-(-x)-7$

Subtracting a negative is the same as adding a positive.

$8 x^{2} + 5 - 3 x^{2} + x - 7$ $8x^2+5-3x^2+x-7$

Combine like terms.

$8 x^{2} - 3 x^{2} + x + 5 - 7$ $8x^2-3x^2+x+5-7$

$5 x^{2} + x - 2$ $5x^2+x-2$

How do you subtract (8x^2 + 5) − (3x^2 − x + 7)(8x2+5)−(3x2−x+7)(8x^2 + 5) − (3x^2 − x + 7)?