How do you Use a Riemann sum to find area?

1 Answer
Oct 10, 2014

The area A of the region under the graph of f above the x-axis from x=a to b can be found by

A=lim_{n to infty}sum_{i=1}^n f(x_i) Delta x,

where x_i=a+iDelta x and Delta x={b-a}/n.

Let us find the area of the region under the graph of y=2x+1 from x=1 to 3.

By definition,

A=lim_{n to infty}sum_{i=1}^n[2(1+2/ni)+1]2/n

by simplifying the expression inside the summation,

=lim_{n to infty}sum_{i=1}^n(8/n^2i+6/n)

by splitting the summation and pulling out constants,

=lim_{n to infty}(8/n^2sum_{i=1}^ni+6/nsum_{i=1}^n1)

by the summation formulas sum_{i=1}^ni={n(n+1)}/2 and sum_{i=1}^n1=n,

=lim_{n to infty}(8/n^2cdot{n(n+1)}/2+6/ncdot n)

by cancelling out n's,

=lim_{n to infty}[4(1+1/n)+6]=4(1+0)+6=10

I hope that this was helpful.