How do you use cross products to solve #(b-3)/16=5/8#?

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Answer 1 · 2018-05-14T05:10:04

#b=13#

Use cross-multiplication:

#(b-3)/16 = 5/8#

#(b-3)xx8=5xx16#

#(bxx8)+(-3xx8)=80#-----> opening the brackets and multiplying through

#8b+(-24)=80#
#8b-24=80#

#8b=80+24#

#8b=104#

#b=104/8#

#b=13#