How do you use factoring to solve this equation $3 x^{2} - 12 x = - 12$ $3x^2-12x=-12$ ?

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Answer 1 · 2015-05-27T00:44:32

Rewrite $3 x^{2} - 12 x = - 12$ $3x^2-12x = -12$
as
$3 x^{2} - 12 x + 12 = 0$ $3x^2-12x+12 = 0$

Factor out the constant $3$ $3$
$3 (x^{2} - 4 x + 4) = 0$ $3(x^2-4x+4) = 0$

Factor the expression
$3 (x - 2) (x - 2) = 0$ $3(x-2)(x-2) = 0$

This can only be true if $(x - 2) = 0$ $(x-2) = 0$

Therefore $x = 2$ $x=2$

How do you use factoring to solve this equation 3x2−12x=−123x^2-12x=-12?