How do you use Integration by Substitution to find #inttan(x)*sec^3(x)dx#?
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1 Answer
Aug 4, 2014
#=(sec^3(x))/3+c# , where#c# is a constantExplanation
#=inttan(x)*sec^3(x)dx# let's have
#secx=t#
#sec(x)*tan(x)dx=dt#
#=int(tan(x)sec(x))*sec^2(x)dx#
#=intt^2dt# , which is quite straight forward,
#=t^3/3+c# , where#c# is a constant
#=(sec^3(x))/3+c# , where#c# is a constant
