How do you use Integration by Substitution to find intx/(x^4+1)dx?

1 Answer
Sep 8, 2014

Let u=x^2.
By taking the derivative,
{du}/{dx}=2x
by taking the reciprocal,
Rightarrow{dx}/{du}=1/{2x}
by multiplying by du,
Rightarrow dx={du}/{2x}

By rewriting the integral in terms of u,
intx/{x^4+1}dx=intx/{u^2+1}cdot{du}/{2x}
by cancelling out x's,
=1/2 int1/{1+u^2}du=1/2tan^{-1}u+C
by putting u=x^2 back in,
=1/2tan^{-1}(x^2)+C