How do you use long division to divide $(x^{4} + 5 x^{3} + 6 x^{2} - x - 2) \div (x + 2)$ $(x^4+5x^3+6x^2-x-2)div(x+2)$ ?

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How do you use long division to divide $(x^{4} + 5 x^{3} + 6 x^{2} - x - 2) \div (x + 2)$ $(x^4+5x^3+6x^2-x-2)div(x+2)$ ?

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Answer 1 · 2017-01-28T06:45:28

The answer is $= x^{3} + 3 x^{2} - 1$ $=color(blue)(x^3+3x^2-1)$

Explanation:

Let's do the long division

$a a a a$ $color(white)(aaaa)$ $x^{4} + 5 x^{3} + 6 x^{2} - x - 2$ $x^4+5x^3+6x^2-x-2$ $a a a a$ $color(white)(aaaa)$ $∣ ∣$ $||$ $x + 2$ $color(red)(x+2)$

$a a a a$ $color(white)(aaaa)$ $x^{4} + 2 x^{3}$ $x^4+2x^3$ $a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaa)$ $∣ ∣$ $||$ $x^{3} + 3 x^{2} - 1$ $color(blue)(x^3+3x^2-1)$

$a a a a a$ $color(white)(aaaaa)$ $0 + 3 x^{3} + 6 x^{2}$ $0+3x^3+6x^2$

$a a a a a a a$ $color(white)(aaaaaaa)$ $+ 3 x^{3} + 6 x^{2}$ $+3x^3+6x^2$

$a a a a a a a a a a$ $color(white)(aaaaaaaaaa)$ $+ 0 + 0 - x - 2$ $+0+0-x-2$

$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $- x - 2$ $-x-2$

$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $- 0 - 0$ $-0-0$

The quotient is $= x^{3} + 3 x^{2} - 1$ $=color(blue)(x^3+3x^2-1)$

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How do you use long division to divide $(x^{4} + 5 x^{3} + 6 x^{2} - x - 2) \div (x + 2)$ $(x^4+5x^3+6x^2-x-2)div(x+2)$ ?

1 Answer

Explanation:

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How do you use long division to divide (x^4+5x^3+6x^2-x-2)div(x+2)(x4+5x3+6x2−x−2)÷(x+2)(x^4+5x^3+6x^2-x-2)div(x+2)?

1 Answer

Explanation:

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How do you use long division to divide $(x^{4} + 5 x^{3} + 6 x^{2} - x - 2) \div (x + 2)$ $(x^4+5x^3+6x^2-x-2)div(x+2)$ ?