How do you use solve $x^{2} - 24 = 0$ $x^2 - 24 = 0$ ?

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Answer 1 · 2016-01-23T01:31:25

$x = \pm 2 \sqrt{3}$ $x=+-2sqrt3$

Add $24$ $24$ to both sides:

$x^{2} = 24$ $x^2=24$

Take the square root of both sides:

$x = \pm \sqrt{24}$ $x=+-sqrt24$

$x = \pm \sqrt{2^{2} \times 3}$ $x=+-sqrt(2^2xx3)$

$x = \pm 2 \sqrt{3}$ $x=+-2sqrt3$

How do you use solve x^2 - 24 = 0x2−24=0x^2 - 24 = 0?