How do you use the amplitude and period to graph $y= 2 sin (-2x+pi) +1$ ?

Question

2304 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-28T02:20:36

As detailed below.

Standard form of equation $y = A sin(Bx - C) + D$ , where

$Amplitude = |A| , " Period " = (2pi)/|B|, " Phase shift " = (-C) / B, " Vertical Shift = D$

Given equation is y = 2 sin (-2x + pi) + 1#

$Amplitude = |A| = 2$

$"Period " = (2pi)/ |B| = (2pi)/ /|- 2| = pi$

$"Phase Shift " = (-C) / B = -pi / -2 = pi/2, " " (color(green)(pi/2 " to the right"))$

$" Vertical Shift " = D = 1$

graph{-2sin(2x-pi) + 1 [-10.125, 9.875, -4.84, 5.16]}

How do you use the amplitude and period to graph y= 2 sin (-2x+pi) +1y= 2 sin (-2x+pi) +1?