How do you use the amplitude and period to graph $y=cos(x°+45°)-1$ ?

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Answer 1 · 2016-05-21T09:37:26

Amplitude is $1$ and period is $2pi$ .

In a typical sine or cosine function $y=alphacos(betax+gamma)+delta$ ,

$alpha$ denotes amplitude,

period is $(2pi)/beta$ or $360^o/beta$

phase shift is given by $(-gamma)/beta$

and $delta$ denotes vertical shift.

Hence in $cos(x^o+45^o) -1$

Amplitude is $1$ and period is $2pi$ .

graph{cos(x+pi/4) -1 [-10, 10, -5, 5]}

How do you use the amplitude and period to graph y=cos(x°+45°)-1y=cos(x°+45°)-1?