How do you use the amplitude and period to graph $y = - cos (x - \frac{π}{4})$ $y = -cos ( x- pi/4)$ ?

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How do you use the amplitude and period to graph $y = - cos (x - \frac{π}{4})$ $y = -cos ( x- pi/4)$ ?

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Answer 1 · 2016-03-02T20:49:19

$A = 1, B = 1, C = 0 \to y = 0, D = \frac{π}{4}, P = \frac{2 π}{B} = 2 π$ $A=1, B=1,C=0->y=0,D=pi/4, P=(2pi)/B=2pi$ Increments: $\frac{P}{4} = \frac{2 π}{4} = \frac{π}{2}$ $P/4=(2pi)/4=pi/2$

Explanation:

Start from the sinusoidal axis y=C which happens to be the x-axis here since sinusoidal equation is y=0. From y=0 go up one unit to y=1 and draw the upper bound then go down one unit and draw the lower bound. Your graph will start on the x-axis from $\frac{π}{4}$ $pi/4$ and add $\frac{π}{2}$ $pi/2$ each time to get to the next mark. Remember that you only need five points to graph one cycle of the sinusoidal equation.

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How do you use the amplitude and period to graph $y = - cos (x - \frac{π}{4})$ $y = -cos ( x- pi/4)$ ?

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How do you use the amplitude and period to graph $y = - cos (x - \frac{π}{4})$ $y = -cos ( x- pi/4)$ ?