How do you use the fundamental identities to simplify $\frac{cot x}{csc x}$ $cotx/cscx$ ?

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How do you use the fundamental identities to simplify $\frac{cot x}{csc x}$ $cotx/cscx$ ?

1 Answer

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Answer 1 · 2017-01-16T15:01:44

The answer is $= cos x$ $=cosx$

Explanation:

$cot x = \frac{cos x}{sin x}$ $cotx=cosx/sinx$

$csc x = \frac{1}{sin x}$ $cscx=1/sinx$

Therefore,

$\frac{cot x}{csc x} = \frac{\frac{cos x}{sin x}}{\frac{1}{sin x}} = \frac{cos x}{sin x \cdot \frac{1}{sin x}}$ $cotx/cscx=(cosx/sinx)/(1/sinx)=cosx/(sinx*1/sinx)$

$= cos x$ $=cosx$

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How do you use the fundamental identities to simplify $\frac{cot x}{csc x}$ $cotx/cscx$ ?

1 Answer

Explanation:

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How do you use the fundamental identities to simplify $\frac{cot x}{csc x}$ $cotx/cscx$ ?