How do you use the slope formula to find the slope of the line containing the points $(\frac{7}{4}, - \frac{5}{8})$ $(7/4, -5/8)$ and $(- \frac{2}{5}, - \frac{8}{5})$ $(-2/5, -8/5)$ ?

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Answer 1 · 2016-11-30T18:16:35

Please see the explanation.

Given two points, $(x_{0}, y_{0}) and (x_{1}, y_{1})$ $(x_0,y_0) and (x_1,y_1)$ , the slope, m. of the line segment connecting them is:

$m = \frac{y_{1} - y_{0}}{x_{1} - x_{0}}$ $m = (y_1 - y_0)/(x_1 - x_0)$

Given: $(\frac{7}{4}, - \frac{5}{8}) and (- \frac{2}{5}, - \frac{8}{5})$ $(7/4, - 5/8) and (-2/5,-8/5)$

$m = \frac{- \frac{8}{5} - - \frac{5}{8}}{- \frac{2}{5} - \frac{7}{4}}$ $m = (-8/5 - -5/8)/(-2/5 - 7/4)$

$m = \frac{- \frac{8}{5} + \frac{5}{8}}{- \frac{2}{5} - \frac{7}{4}} \frac{40}{40}$ $m = (-8/5 + 5/8)/(-2/5 - 7/4)40/40$

$m = \frac{- 64 + 25}{- 16 - 70}$ $m = (-64 + 25)/(-16 - 70)$

$m = \frac{- 39}{- 86}$ $m = (-39)/(-86)$

$m = \frac{39}{86}$ $m = 39/86$

How do you use the slope formula to find the slope of the line containing the points (7/4, -5/8)(74,−58)(7/4, -5/8) and (-2/5, -8/5)(−25,−85)(-2/5, -8/5)?