Question

How do you use transformation to graph the cosine function and determine the amplitude and period of `y=2cos(1/3x)`?

Answer 1

Amplitude: `2` Period: `6pi`

Explanation:

For a cosine function in the form

`y=Acos(bx),` the amplitude is given by `|A|` and the period by `P=(2pi)/b`

Here, `A=2,` so the amplitude is `|2|=2`

`b=1/3, P=(2pi)/(1/3)=2pi*3=6pi`