How do you write ${(\frac{1}{4})}^{- 6} = 4096$ $(1/4)^-6=4096$ in log form?

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Answer 1 · 2016-06-15T04:52:56

${log}_{\frac{1}{4}} 4096 = - 6$ $log_(1/4)4096=-6$

As $a^{b} = c$ $a^b=c$ can be written as ${log}_{a} c = b$ $log_ac=b$

${(\frac{1}{4})}^{- 6} = 4096$ $(1/4)^(-6)=4096$ can be written as

${log}_{\frac{1}{4}} 4096 = - 6$ $log_(1/4)4096=-6$

How do you write (1/4)^-6=4096(14)−6=4096(1/4)^-6=4096 in log form?