How do you write $\frac{1.68 \times 10^{- 1}}{3 \times 10^{4}}$ $(1.68 times 10^-1) / (3 times 10^4)$ in standard form?

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Answer 1 · 2015-10-19T11:11:24

You can do this in two ways: First the standard forms and then the division, or the other way around. I prefer the second.

Rules of division: divide the numbers, subtract the 10-powers:

$= \frac{1.68}{3} \cdot 10^{- 1 - 4} = 0.56 \cdot 10^{- 5}$ $=1.68/3*10^(-1-4)=0.56*10^-5$

Since the 10-power is negative, we move the decimal point 5 to the left:

$= 0.0000056$ $=0.0000056$

The other way would be:
$\frac{0.168}{30000} =$ $0.168/30000=$ (same answer of course)

How do you write (1.68 times 10^-1) / (3 times 10^4)1.68×10−13×104(1.68 times 10^-1) / (3 times 10^4) in standard form?