How do you write 2 +4i in trigonometric form?

1 Answer
Apr 12, 2018

2sqrt5(cos(1.107)+isin(1.107))

Explanation:

"to convert to trigonometric form"

"that is "x+yitor(costheta+isintheta)" using"

•color(white)(x)r=sqrt(x^2+y^2)

•color(white)(x)theta=tan^-1(y/x);-pi < theta <=pi

"here "x=2" and "y=4

rArrr=sqrt(2^2+4^2)=sqrt20=2sqrt5

theta=tan^-1(2)=1.107" radians to 3 dec. places"

rArr2+4i=2sqrt5(cos(1.107)+isin(1.107))