How do you write #3=rcos(theta-60)# in rectangular form? Trigonometry The Polar System Converting Between Systems 1 Answer A. S. Adikesavan Nov 29, 2016 #x+sqrt3y=6# Explanation: The conversion formula is #r ( cos theta, sin theta ) = ( x, y )# Here, #3 =r(cos theta cos 60^o+sin theta sin 60^0)# #=1/2(r cos theta) +sqrt 3/2(r sin theta )# #=1/2(x+sqrt3 y)# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 3094 views around the world You can reuse this answer Creative Commons License