How do you write $32=x^5$ in Logarithm form?

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Answer 1 · 2016-08-28T20:04:29

$32=x^5 iff 5=log_x 32$ .

Answer 2 · 2016-08-28T20:04:43

It can be written:

$log_x 32 = 5 " "$ or $" " log_32 x = 1/5$

Given:

$32 = x^5$

If we take logs base $x$ we find:

$log_x 32 = log_x x^5 = 5$

Alternatively, if we take logs base $32$ we find:

$1 = log_32 32 = log_32 x^5 = 5 log_32 x$

Hence:

$log_32 x = 1/5$

How do you write 32=x^532=x^5 in Logarithm form?