How do you write $(3w^2-8w-6)-(4w^2+4w-4)$ in standard form?

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Answer 1 · 2017-01-16T18:31:33

$-w^2 - 12w - 2$

First, remove all the terms from parenthesis:

$3w^2 - 8w - 6 - 4w^2 - 4w + 4$

Next, group like terms:

$3w^2 - 4w^2 - 8w - 4w - 6 + 4$

Now group like terms:

$(3 - 4)w^2 + (-8 - 4)w - 2$

$-1w^2 - 12w - 2$

$-w^2 - 12w - 2$

How do you write (3w^2-8w-6)-(4w^2+4w-4)(3w^2-8w-6)-(4w^2+4w-4) in standard form?