How do you write $(3x^2-4)+(5x^2+8)$ in standard form?

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Answer 1 · 2017-06-07T15:35:13

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$3x^2 - 4 + 5x^2 + 8$

Next, group like terms:

$3x^2 + 5x^2 - 4 + 8$

Now, combine like terms:

$(3 + 5)x^2 + (-4 + 8)$

$8x^2 + 4$

How do you write (3x^2-4)+(5x^2+8)(3x^2-4)+(5x^2+8) in standard form?