How do you write $(3x^2 + 7) – (x^2 – 6x + 4)$ in standard form?

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Answer 1 · 2016-05-30T08:48:43

$2x^2+6x+3$

The minus sign in front of $-(x^2-6x+4)$ means that you multiply everything inside the brackets by $(-1)$

So $color(brown)(-(x^2-6x+4)" "color(blue)(->" "-x^2+6x-4)$

$color(green)("Putting it all together")$

$color(brown)((3x^2+7)-(x^2-6x+4)" "color(blue)(->" "3x^2+7-x^2+6x-4)$

$color(green)("Grouping like terms")$

$(3x^2-x^2)+(+6x)+(7-4)" "->" "2x^2+6x+3$

How do you write (3x^2 + 7) – (x^2 – 6x + 4) (3x^2 + 7) – (x^2 – 6x + 4) in standard form?