How do you write $3x-4y-10=0$ in polar form?

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Answer 1 · 2017-11-06T17:33:26

$r=10/(3costheta-4sintheta)$

we have the conversion eqns

$r^2=x^2+y^2--(1)$

$x=rcostheta--(2)$

$y=rsintheta---(3)$

we have

$3x-4y-10=0$

using $(2)" & "(3)$

$3rcostheta-4rsintheta-10=0$

$r(3costheta-4sintheta)=10$

$r=10/(3costheta-4sintheta)$

How do you write 3x-4y-10=03x-4y-10=0 in polar form?