How do you write $(3 x^{6} - x^{4} - 3 x^{2} - 1) - (9 + 3 x^{3} + x^{2} + x 5)$ $(3x^6 - x^4 - 3x^2 - 1) - (9 + 3x^3 + x^2 + x5)$ in standard form?

Question

1379 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-28T23:24:28

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

$3 w^{6} - x^{4} - 3 x^{2} - 1 - 9 - 3 x^{3} - x^{2} - x^{5}$ $3w^6 - x^4 - 3x^2 - 1 - 9 - 3x^3 - x^2 - x^5$

Next, group like terms in descending order of their exponents:

$3 w^{6} - x^{5} - x^{4} - 3 x^{3} - 3 x^{2} - x^{2} - 1 - 9$ $3w^6 - x^5 - x^4 - 3x^3 - 3x^2 - x^2 - 1 - 9$

Now, combine like terms:

$3 w^{6} - x^{5} - x^{4} - 3 x^{3} + (- 3 - 1) x^{2} + (- 1 - 9)$ $3w^6 - x^5 - x^4 - 3x^3 + (-3 - 1)x^2 + (-1 - 9)$

$3 w^{6} - x^{5} - x^{4} - 3 x^{3} + (- 4) x^{2} + (- 10)$ $3w^6 - x^5 - x^4 - 3x^3 + (-4)x^2 + (-10)$

$3 w^{6} - x^{5} - x^{4} - 3 x^{3} - 4 x^{2} - 10$ $3w^6 - x^5 - x^4 - 3x^3 - 4x^2 - 10$

How do you write (3x^6 - x^4 - 3x^2 - 1) - (9 + 3x^3 + x^2 + x5)(3x6−x4−3x2−1)−(9+3x3+x2+x5)(3x^6 - x^4 - 3x^2 - 1) - (9 + 3x^3 + x^2 + x5) in standard form?