How do you write $- 5 x + 12 = 20$ $-5x+12=20$ in slope intercept form?

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Answer 1 · 2014-11-28T20:57:52

$- 5 x + 12 = 20$ $-5x+12=20$

by subtracting $12$ $12$ ,

$\Rightarrow - 5 x = 8$ $=> -5x=8$

by dividing by $- 5$ $-5$ ,

$\Rightarrow x = - \frac{8}{5}$ $=> x=-8/5$ ,

which is a vertical line, whose slope is undefined, so it cannot be written in Slope-Intercept Form.

I hope that this was helpful.

How do you write -5x+12=20−5x+12=20-5x+12=20 in slope intercept form?