How do you write a rule for the nth term of the arithmetic sequence and then find $a_{22}$ $a_22$ given $d = 14, a_{6} = - 10$ $d=14, a_6=-10$ ?

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Answer 1 · 2017-09-09T11:31:45

$a_{n} = a_{1} + (n - 1) d, a_{22} = 214$ $a_n= a_1+(n-1)d , a_22=214$

For arithmatic progression series ,

$n$ $n$ th term is $a_{n} = a_{1} + (n - 1) d$ $a_n= a_1+(n-1)d$ , where $a_{1} . n, d$ $a_1.n,d$ are

first term , number of terms and common difference respectively.

$a_6=-10 , d=14 , n=6 , a_1= ? :. -10 = a_1+(6-1)*14$

or $a_1= -10-70= -80 ; a_22=?$

$a_22= a_1+(n-1)d or a_22= -80 +(22-1)*14$ or

$a_22= -80 +294 =214$ [Ans]

How do you write a rule for the nth term of the arithmetic sequence and then find a_22a22a_22 given d=14, a_6=-10d=14,a6=−10d=14, a_6=-10?