How do you write an equation for the nth term of the geometric sequence $64,16,4,....$ ?

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Answer 1 · 2017-01-02T09:16:09

$64(1/4)^(n-1)$

This is a geometric sequence with starter

a = 64 and common ratio

r = 16/64=4/16=1/4 ..

The generall $(n^(th))$ term is

$ar^(n-1)$

$=64(14)^(n-1)$

For exemplification,

the $4^(th)$ term is $64(1/4)^3=64/64=1$ and

the $10^(th)$ term is $64(1/4)^9=64/262144=1/4096$ .

How do you write an equation for the nth term of the geometric sequence 64,16,4,....64,16,4,....?