How do you write an equation for the nth term of the geometric sequence #64,16,4,....#?

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Answer 1 · 2017-01-02T09:16:09

#64(1/4)^(n-1)#

This is a geometric sequence with starter

a = 64 and common ratio

r = 16/64=4/16=1/4 ..

The generall #(n^(th))# term is

#ar^(n-1)#

#=64(14)^(n-1)#

For exemplification,

the #4^(th)# term is #64(1/4)^3=64/64=1# and

the #10^(th)# term is #64(1/4)^9=64/262144=1/4096#.