How do you write an equation given point (-2,3) slope -1?

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Answer 1 · 2016-11-12T03:53:29

$y = -1x + 1$

We can use the point-slope form of the equation to plug in values and solve for the equation.

use the slope of $-1$ and the point of $(-2,3)$

$m=-1$
$x_1 = -2$
$y_1 = 3$

The point-slope formula equation is

$y - y_1 = m(x - x_1)$

plug in the values

$y - 3 = -1(x - (-2))$ simplify the signs

$y - 3 = -1(x + 2)$ distribute the $-1$

$y - 3 = -1x - 2$ use additive inverse to isolate the $y$

$y cancel(- 3) cancel(+ 3)= -1x - 2 + 3$ simplify

$y = -1x + 1$

Answer 2 · 2016-11-12T03:55:16

Point-slope form: $y-3=-(x+2)$

Y-intercept form: $y=-x+1$

Use the point-slope equation: $y-y_1=m(x-x_1)$ , where $(x_1,y_1)$ is the given point $(-2,3)$ , and $m$ is the slope $-1$ .

Plug the numbers into the equation.

$y-3=-1(x-(-2))$

Simplify.

$y-3=-(x+2)$

Solve for $y$ to get the slope-intercept form $y=mx+b$ , where $m$ is the slope and $b$ is the y-intercept.

Add $3$ to both sides.

$y=-x-2+3$

Simplify.

$y=-x+1$ ,

where $m=-1$ and $b=1$ .

graph{y=-x+1 [-10, 10, -5, 5]}