How do you write an equation going through points (-5, 1) (0, -2)?

Question

2642 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-31T16:21:35

The standard form of the equation would be
$5y +3x= -10$

The formula for the slope of a line based upon two coordinate points is

$m = (y_2-y_1)/(x_2-x_1)$

For the coordinate points $(-5,1) and (0,-2)$
$x_1 = -5$
$x_2 = 0$
$y_1 = 1$
$y_2 = -2$

$m = (-2-1)/(0-(-5))$

$m = -3/5$

The slope is $m = -3/5$

The point slope formula would be written as
$y - y_1 = m( x - x_1)$

$m = -3/5$
$x_1 = -5$
$y_1=1$

$y - 1 = -3/5 (x -(-5))$

$y - 1 = -3/5x -3$

$y cancel(-1) cancel(+ 1)= -3/5x -3 +1$

$y = -3/5x -2$

The slope-intercept form of the equation of the line is
$y = -3/5x -2$

$(5)y = (-3/5x -2)(5)$

$5y =-3x-10$

$5y +3x=cancel(-3x) cancel(+3x)-10$

The standard form of the equation would be
$5y +3x= -10$