How do you write an equation of a line given (1,-3) and (-2,-4)?
1 Answer
Jun 17, 2017
Explanation:
"the equation of a line in "color(blue)"slope-intercept form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))
where m represents the slope and b the y-intercept.
"to calculate m use the" color(blue)" gradient formula"
color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))
where(x_1,y_1),(x_2,y_2)" are 2 points"
"the points are " (x_1,y_1)=(1,-3),(x_2,y_2)=(-2,-4)
rArrm=(-4-(-3))/(-2-1)=(-1)/(-3)=1/3
rArry=1/3x+blarr" is partial equation"
"substitute either of the 2 points into the partial equation"
"to obtain b"
"using " (1,-3)
-3=1/3+brArrb=-3-1/3=-10/3
rArry=1/3x-10/3larrcolor(red)" in slope-intercept form"