How do you write an equation of a line given (1,-3) and (-2,-4)?

1 Answer
Jun 17, 2017

y=1/3x-10/3

Explanation:

"the equation of a line in "color(blue)"slope-intercept form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))
where m represents the slope and b the y-intercept.

"to calculate m use the" color(blue)" gradient formula"

color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))
where (x_1,y_1),(x_2,y_2)" are 2 points"

"the points are " (x_1,y_1)=(1,-3),(x_2,y_2)=(-2,-4)

rArrm=(-4-(-3))/(-2-1)=(-1)/(-3)=1/3

rArry=1/3x+blarr" is partial equation"

"substitute either of the 2 points into the partial equation"
"to obtain b"

"using " (1,-3)

-3=1/3+brArrb=-3-1/3=-10/3

rArry=1/3x-10/3larrcolor(red)" in slope-intercept form"