How do you write an equation of a line given (-7, 9) and (3, -7)?

1 Answer
Mar 30, 2017

See the entire solution process below:

Explanation:

First, we must determine the slope. The slope can be found by using the formula: m = (color(red)(y_2) - color(blue)(y_1))/(color(red)(x_2) - color(blue)(x_1))

Where m is the slope and (color(blue)(x_1, y_1)) and (color(red)(x_2, y_2)) are the two points on the line.

Substituting the values from the points in the problem gives:

m = (color(red)(-7) - color(blue)(9))/(color(red)(3) - color(blue)(-7)) = (color(red)(-7) - color(blue)(9))/(color(red)(3) + color(blue)(7)) = -16/10 = -8/5

Now, we can use the point-slope formula to write and equation for the line. The point-slope formula states: (y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))

Where color(blue)(m) is the slope and color(red)(((x_1, y_1))) is a point the line passes through.

Substituting the slope we calculated and the first point from the problem gives:

(y - color(red)(9)) = color(blue)(-8/5)(x - color(red)(-7))

Solution 1: (y - color(red)(9)) = color(blue)(-8/5)(x + color(red)(7))

We can also substitute the slope we calculated and the second point from the problem giving:

(y - color(red)(-7)) = color(blue)(-8/5)(x - color(red)(3))

Solution 2: (y + color(red)(7)) = color(blue)(-8/5)(x - color(red)(3))

Or, we can solve the first or second equation for y and write the equation in slope intercept form. The slope-intercept form of a linear equation is: y = color(red)(m)x + color(blue)(b)

Where color(red)(m) is the slope and color(blue)(b) is the y-intercept value.

y + color(red)(7) = (color(blue)(-8/5) xx x) - (color(blue)(-8/5) xx color(red)(3))

y + color(red)(7) = -8/5x - (-24/5)

y + color(red)(7) = -8/5x + 24/5

y + color(red)(7) - 7 = -8/5x + 24/5 - 7

y + 0 = -8/5x + 24/5 - (5/5 xx 7)

y + 0 = -8/5x + 24/5 - 35/5

Solution 3: y = color(red)(-8/5)x - color(blue)(11/5)