How do you write an equation of a line given point (-3,0) and (1,-6)?

1 Answer
Binayaka C.
Jul 3, 2016

The equation of the line is y=-3/2x-9/2y=−32x−92

Explanation:

The slope of the line passing through the given points is m=(y_2-y_1)/(x_2-x_1)=(-6-0)/(1-(-3))=-6/4=-3/2m=y2−y1x2−x1=−6−01−(−3)=−64=−32 The equation of the line passing through point (-3,0)(−3,0) is y-y_1=m(x-x_1) or y-0=-3/2(x+3)or y=-3/2x-9/2y−y1=m(x−x1)ory−0=−32(x+3)ory=−32x−92 graph{(-3/2)*x-9/2 [-10, 10, -5, 5]}[Ans]

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