How do you write an equation of a line given point (-8,5) and m=-2/5?

1 Answer
Jan 15, 2017

See entire explanation below

Explanation:

To write an equation for this line give the slope and one point use the point-slope formula.

The point-slope formula states: (y - color(red)(y_1)) = color(blue)(m)(x - color(red)(x_1))

Where color(blue)(m) is the slope and color(red)(((x_1, y_1))) is a point the line passes through.

Substituting the point and slope from the problem gives:

(y - color(red)(5)) = color(blue)(-2/5)(x - color(red)(-8))

(y - color(red)(5)) = color(blue)(-2/5)(x + color(red)(8))

Or, we can solve for y to put this equation in the more familiar slope-intercept form:

The slope-intercept form of a linear equation is:

y = color(red)(m)x + color(blue)(b)

Where color(red)(m) is the slope and color(blue)(b is the y-intercept value.

y - color(red)(5) = color(blue)(-2/5)x + (color(blue)(-2/5) xx color(red)(8))

y - color(red)(5) = color(blue)(-2/5)x - 16/5

y - color(red)(5) + 5 = color(blue)(-2/5)x - 16/5 + 5

y - 0 = -2/5x - 16/5 + (5/5 xx 5)

y = -2/5x - 16/5 + 25/5

y = -2/5x + 9/5